HELP ASAP PLEASE Part A: Explain why the x-coordinates of the points where the graphs of the equations y = 4x and y = 2x−1 intersect are the solutions of the equation 4x = 2x−1. (4 points)Part B: Make tables to find the solution to 4x = 2x−1. Take the integer values of x between −4 and 4. (4 points)Part C: How can you solve the equation 4x = 2x−1 graphically? (2 points)
Accepted Solution
A:
A. The (x,y) coordinates where the equations y =4x and y = 2x - 1 intersect on a graph is the solution to that system of equations. When solving for this system of equations by substitution of y, the equation 4x = 2x -1 is obtained. So the x-coordinate obtained is both a solution to the equation 4x = 2x - 1 and the intersection point of the system of equations y = 4x and y = 2x - 1.
B. Idk about this part... Says to make a tables to solve for 4x = 2x - 1. If you make a table for Eq. #1. y = 4x and Eq. #2. y = 2x -1 maybe..
the solution to 4x = 2x - 1 ; the x-coordinate is not an integer value so Idk what the point of this is..... 4x = 2x - 1 4x - 2x = -1 2x = -1 x = -1/2 not an integer..
C. You can solve the equation 4x = 2x - 1 graphically by graphing y = 4x and y = 2x - 1 and identifying the x-coordinate at the point of intersection.