Q:

The width of a box is 1 cm less than its length. The height of the box is 9 cm greater than the length. The dimensions can be represented by x, x βˆ’ 1, and x + 9. Multiply the dimensions and find the greatest common factor of the terms.A. x^4B. x^3C. x^2D. x

Accepted Solution

A:
Answer:D. xStep-by-step explanation:The dimensions are:[tex]x(x-1)(x+9)[/tex]We multiply out the dimensions to obtain;[tex]x(x^2+9x-x-9)[/tex][tex]x(x^2+8x-9)[/tex][tex]x^3+8x^2-9x[/tex]The terms are:[tex]x^3[/tex][tex]8x^2=2^3x^2[/tex][tex]-9x=-3^2x[/tex]The highest common factor is the product of the least powers of th comon factors.TheHCF is x